A time for the 100 meter sprint of 14.9 seconds at a school where the mean time for the 100 meter sprint is 17.6 seconds and the standard deviation is 2.1 seconds. What is the z-score for this observation?

1 Answer

#z=-1.285714#

Explanation:

The formula for the z-score

#z=(x-mu)/sigma#

where #z=# z-score
#mu=# mean
#sigma=#standard deviation
#x=#raw score

Given: #x=14.9# and #mu=17.6# and #sigma=2.1#

#z=(x-mu)/sigma=(14.9-17.6)/2.1=-1.285714#

God bless....I hope the explanation is useful.