A train goes forward at a speed of 1 m/s for 20 seconds. Then it stops and goes backward at a speed of 0.5m/s for 4 seconds. After both movements are completed how far is the train located from its starting point?

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Answer 1 · 2018-03-05T18:05:42

#18m#

Calculating net displacement along the direction of its first journey,it is #1*20 - 0.5*4=18m#

so,this is the distance by which it lies infront of its point of journey.