# A triangle has corners at (6 ,6 ), (7 ,4 ), and (1 ,2 ). How far is the triangle's centroid from the origin?

Distance of the centroid from origin is $6.15 \left(2 \mathrm{dp}\right)$ unit
Centroid of triangle is at $\left(\frac{{x}_{1} + {x}_{2} + {x}_{3}}{3} , \frac{{y}_{1} + {y}_{2} + {y}_{3}}{3}\right) \mathmr{and} \left(\frac{6 + 7 + 1}{3} , \frac{6 + 4 + 2}{3}\right) \mathmr{and} \left(4.67 , 4\right)$Distance of the centroid from origin is$d = \sqrt{{\left(4.67 - 0\right)}^{2} + {\left(4 - 0\right)}^{2}} = 6.15 \left(2 \mathrm{dp}\right)$unit [Ans]