# A triangle has sides A, B, and C. If the angle between sides A and B is (pi)/3, the angle between sides B and C is pi/3, and the length of B is 17, what is the area of the triangle?

Area$= \frac{\sqrt{3}}{4} \cdot {17}^{2} = \frac{289 \sqrt{3}}{4} = 125.141 \text{ }$square units

#### Explanation:

The triangle is an equiangular triangle with all angles$= \frac{\pi}{3} = {60}^{\circ}$

Formula for the area$= \frac{\sqrt{3}}{4} \cdot {s}^{2}$

with side $s = 17$

we compute the Area$= \frac{\sqrt{3}}{4} \cdot {17}^{2} = \frac{289 \sqrt{3}}{4} = 125.141 \text{ }$square units

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