# A triangle that is 3 units high, 4 units long, and has a hypotenuse of 5 units, how do you find the angles?

${3}^{2}$ + ${4}^{2}$ = ${5}^{2}$ $\implies$ the triangle is right angled$\implies$ 0ne angle is ${90}^{0}$ . Smallest angle is ${\tan}^{-} 1$ (3/4) = ${36.87}^{0}$ and the other angle is ${\tan}^{-} 1$ (4/3) = ${53.13}^{0}$