Question

A triangular-shaped wall has a base of `2x+4` and a height of `x+3`. The area of the triangle is `56 i n^2`. What is the value of `x`?

Answer 1

`x=5`in

Explanation:

by the condition
area`=1/2*b*h=1/2(2x+4)xx(x+3)=56`
`=>x^2+5x+6-56=0`
`=>x^2+10x-5x-50=0`
`=>x(x+10)-5(x+10)=0`
`=>(x+10)(x-5)=0`
possible solution `x=5`in