A tube filled with mercury has a resistance of 15ohm at 0 degrees, if the tube is heated up to 65degrees what will be the resistance? Take the tube temperature coefficient of resistance as 0,0042ohm/degree

Question

464 views around the world

You can reuse this answer
Creative Commons License

Answer 1 · 2018-05-15T15:28:57

The resistance is #=19.1Omega#

Apply the equation

#R_t=R_0(1+alpha DeltaT)#

The resistance at #0^@C# is #R_0=15 Omega#

The change in temperature is

#DeltaT=65 ^@C#

The temperature coefficient of resistance is

#alpha=0.0042Omega^@C^-1#

Therefore,

The resistance at #65^@C# is

#R_t=15*(1+0.0042*65)=19.1Omega#