# A voltaic cell which is constructed with Sn+2/Sn (Ereduction=-0.14V) and Zn+2/Zn (Eoxidation=-0.76V) is represented by Zn|Zn+2(1M)||Sn+2|Sn(1M). What is the emf of the cell?

Apr 22, 2017

${E}_{\textrm{c e l l}} = \text{+0.62 V}$

#### Explanation:

To answer this question, we determine the standard potential of the voltaic cell using the two half-cell potentials.

$\textcolor{w h i t e}{m m m m m m m m m m m m m m m m m m m m m m m m m m m} {E}^{\circ} \text{/V}$
Anode: color(white)(m)1×["Zn(s)" → "Zn"^"2+""(aq)" + "2e"^"-"]color(white)(mmmmmmml)"+0.76"
Cathode: 1×["Sn"^"2+""(aq)" +"2e"^"-" → "Sn(s)"]color(white)(mmmmmmmm)"-0.14"
Cell: $\textcolor{w h i t e}{m m m m l l} \text{Zn(s)" + "Sn"^"2+""(aq)" →"Zn"^"2+""(aq)" + "Sn(s)"color(white)(m)"+0.62}$

${E}_{\textrm{c e l l}}^{\circ} = \text{+0.62 V}$