Algebra 2 question? Matrices question

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2 Answers
Apr 17, 2018

Part a
This reference on Matrix multiplication tells us that when we multiply a #1 xx2# matrix by a #2 xx 4# matrix we will obtain a #1xx4# matrix. It is important to know the dimensions of the resulting matrix because you will, then, know how many rows and columns of #c_(ij)s# that you must compute. You start with #c_11, c_12, c_13,..., c_1j# then do the same with row 2, row 3, and so on:

In this case, there is only 1 row with 4 columns:

#[(13, 19)]*[(23,21,19,17),(19,13,11,9)]=[(660 , 520 , 456 , 392)]#

Part b

The meaning of the entries in the resulting matrix is the amount of money spent on T-shirts sold in the 4 months, May, June, July, and August, respectively.

We can see that amount spent in May is #$660# and the amount spent August is #$392#; the difference is:

#$660 - $392 = $268#

Apr 18, 2018

#$268# more was spent.

Explanation:

Before you can multiply matrices you have to check whether they are compatible:

A #" " color(red)(1) xx color(blue)(2)" "# matrix and a #" " color(blue)(2) xx color(red)(4)" "# matrix are compatible because the number of columns in the first matrix is the same as the number of rows in the second matrix. This is shown in #color(blue)("blue")#

The answer matrix will be a #" " color(red)(1 xx 4)" "# matrix.

To multiply the matrices:

The values in the row of the first matrix,# [(13,19)] #, must be multiplied by the values in each of the columns of the second matrix.

The products must be added to get the final answer.

#[(13, 19)]*[(color(magenta)(23),color(limegreen)(21),color(darkorange)(19),color(cyan)(17)),(color(magenta)(19),color(limegreen)(13),color(darkorange)(11),color(cyan)(9))]=[color(magenta)(?) " "color(limegreen)(?)" " color(darkorange)(?)" " color(cyan)(?)]#

#[(13, 19)]*[(color(magenta)(23),21,19,17),(color(magenta)(19),13,11,9)]=[color(magenta)(13*23+19*19) " "color(limegreen)(?)" " color(darkorange)(?)" " color(cyan)(?)]#

#[(13, 19)]*[(color(magenta)(23),21,19,17),(color(magenta)(19),13,11,9)]=[color(magenta)(660) " "color(limegreen)(?)" " color(darkorange)(?)" " color(cyan)(?)]#

#[(13, 19)]*[(23,color(limegreen)(21),19,17),(19,color(limegreen)(13),11,9)]=[(660 , color(limegreen)(13*21+19*13) , color(darkorange)(?) color(cyan)(?))]#

#[(13, 19)]*[(23,color(limegreen)(21),19,17),(19,color(limegreen)(13),11,9)]=[(660 , color(limegreen)(520) , color(darkorange)(?)" " color(cyan)(?))]#

#[(13, 19)]*[(23,21,color(darkorange)(19),17),(19,13,color(darkorange)(11),9)]=[(660 , 520 , color(darkorange)(13*19+19*11) color(cyan)(?))]#

#[(13, 19)]*[(23,21,color(darkorange)(19),17),(19,13,color(darkorange)(11),9)]=[(660 , 520 , color(darkorange)(456)" " color(cyan)(?))]#

#[(13,19)]*[(23,21,19,color(cyan)(17)),(19,13,11,color(cyan)(9))]=[(660 , 520 , 456 " " color(cyan)(13*17+19*9))]#

#[(13, 19)]*[(23,21,19,color(cyan)(17)),(19,13,11,color(cyan)(9))]=[(660 , 520 , 456 color(cyan)(392))]#

The final answer is
#[(13, 19)]*[(23,21,19,17),(19,13,11,9)]=[(660 , 520 , 456, 392)]#

The values in the final #1 xx 4# matrix indicate the total amount of money spent on both types of shirts in the months May, June, July and August respectively.

How much more was spent in #color(magenta)("May")# than in #color(cyan)"August"#?

#[(13, 19)]*[(23,21,19,17),(19,13,11,9)]=[color(magenta)(660) , 520 , 456, color(cyan)(392)]#

#$660-$392 = $268#

When multiplying: work across horizontally in the first matrix and vertically in the second matrix.