# Aluminium reacts with sulfuric acid (h2so4) to produce aluminium sulfate al2(so4)3 and hydrogen (h2). Complete the balance the equation for this reaction?

Apr 20, 2018

Balanced Equation:

$2 \text{Al(s)" + 3"H"_2"SO"_4("aq")}$$\rightarrow$$\text{Al"_2("SO"_4)_3("aq") + 3"H"_2("g")}$

#### Explanation:

$\text{Al(s) + H"_2"SO"_4("aq")}$$\rightarrow$$\text{Al"_2("SO"_4)_3("aq") + "H"_2("g")}$

Start with the polyatomic sulfate ion, $\text{SO"_4}$. There is one sulfate ion on the left-hand side and there are three on the right-hand side. Place a coefficient of $3$ in front of $\text{H"_2"SO"4}$.

$\text{Al(s)" + color(red)3"H"_2"SO"_4("aq")}$$\rightarrow$$\text{Al"_2("SO"_4)_3("aq") + "H"_2("g")}$

There are now six hydrogen atoms on the left-hand side and two hydrogen atoms on the right-hand side. Place a coefficient of $3$ in front of $\text{H"_2}$.

$\text{Al(s)" + color(red)3"H"_2"SO"_4("aq")}$$\rightarrow$$\text{Al"_2("SO"_4)_3("aq") + color(purple)3"H"_2("g")}$

There is one aluminum atom on the left-hand side and two on the right-hand side. Place a coefficient of $2$ in front of $\text{Al}$ on the left-hand side.

$\textcolor{g r e e n}{2} \text{Al(s)" + color(red)3"H"_2"SO"_4("aq")}$$\rightarrow$$\text{Al"_2("SO"_4)_3("aq") + color(purple)3"H"_2("g")}$

Number of atoms of each element on each side:

$\text{Left-hand side: 2 Al, 6 H, 3 S, 12 O}$

$\text{Right-hand side: 2 Al, 6 H, 3 S, 12 O}$

Both sides have the same number of atoms of each element and the equation is therefore balanced.