An aeroplan is moving horizontaly with a velocity of 600km per hour at a height of 1960m . when it is vertically above a point "A" on the ground, a bomb is released from it. The bomb strikes the ground at a point 'B'. The distance AB is?

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Answer 1 · 2018-04-11T12:36:27

The distance is #AB=3333.3m#

Resolving in the vertical direction #darr_+#

#h=ut+1/2at^2#

The height is #h=1960m#

The initial velocity is #u=0ms^-1#

The acceleration due to gravity is #a=g=9.8ms^-1#

Therefore,

#1960=0*t+1/2*9.8*t^2#

#t^2=(2*1960)/9.8=400#

#t=sqrt(400)=20s#

Resolving in the horizontal direction #rarr^+#

#d=vt#

The initial velocity is #v=600*1000/3600=166.7ms^-1#

Therefore,

The distance is #AB=166.7*20=3333.3m#