An ancient gold coin is 2.20 cm in diameter and 3.00 mm thick. It is a cylinder and the density of gold is 19.3 grams/cm^3, what is the mass of the coin?

Jan 24, 2017

Approx. $22 \cdot g$
$\rho , \text{density"="mass"/"volume}$
And thus $\text{mass}$ $=$ $\rho \times \text{volume}$, and we know the $\text{volume}$ of a cylinder is $\pi \times {r}^{2} \times l$, where $r = \frac{\text{diameter}}{2}$, and $\text{length}$ is as given.
And thus "mass"=19.3*g*cm^-3xxpixx0.300*cmxx(1.10*cm)^2=??g