An engine performs 17,640 J of work on a scooter. The scooter and rider have a combined mass of 180 kg. lf the scooter started at rest, what is the speed of the bike after the work is performed?

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Answer 1 · 2018-01-11T16:14:13

The speed is #=14ms^-1#

Let the speed of the scooter is #=(v)ms^-1#

The kinetic energy is

#E=1/2mv^2#

The energy is #E=17640J#

The mass is #m=180kg#

The speed is

#v=sqrt((2E)/m)=sqrt((2*17640)/180)#

#=14ms^-1#