# An object is at rest at (6 ,7 ,2 ) and constantly accelerates at a rate of 4/3 m/s^2 as it moves to point B. If point B is at (3 ,1 ,0 ), how long will it take for the object to reach point B? Assume that all coordinates are in meters.

d=sqrt ((6-3)^2+(7-1)^2+(2-0)^2
$\therefore d = 7 m$
$s = \frac{1}{2} a {t}^{2}$
$\therefore 7 = \frac{1}{2} \times \frac{4}{3} \times {t}^{2}$
$\implies t = 3.24 s$