An object is released from rest on a planet that has no atmosphere. The object falls freely for 3.06 m in the first second. What is the magnitude of the acceleration due to gravity on the planet?

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Answer 1 · 2018-03-05T17:26:22

#6.12 ms^-2#

Well we can answer this question just by considering that acceleration due to gravity in that planet is #a#

Now,for constant we can apply the equation,(no atmosphere in the planet means no chance of atmospheric resistance against the motion)

#S=ut + 1/2 at^2# where, #S# is the distance moved due to acceleration #a# at time #t# that started with an initial velocity #u#

Here,we are provided with the informations that #u=0,S=3.06m,t=1#

So,putting the values in the equation we get,

#3.06 =1/2 a ×1^2#

So,#a=6.12 ms^-2#