An object of mass 3 kg moving with velocity 7 M per second is brought to rest in time 4 seconds find force?

1 Answer
Feb 10, 2018

Considering applied force was constant,we can say that the object came to rest due to constant deceleration(#a#)

So,we can apply, #v=u-at# (where, #v# is the velocity of the object,moving under constant deceleration(#a#), after time #t# that had an initial velocity of #u#)

Here, #v=0,u=7 m/s ,t=4s#

So,#a= 7/4 m/s^2#

So,force that was acting against the direction of the object's initial velocity was #m*a=3*(7/4)=21/4 N#