An object travels North at 1 m/s for 3 s and then travels South at 2 m/s for 4 s. What are the object's average speed and velocity?

Sep 19, 2017

As the object goes through north,he overcame the distance (1×3)=3m
As the object goes through south, he overcame (4×2)=8m
Hence,its net displacement is $\left(8 - 3\right) = 5 m$ by south.
Its average speed is (distance covered/time)=$\frac{8 + 3}{3 + 4} = 1.57 m {s}^{-} 1$
and average velocity is(displacement/time) $= \frac{5}{3 + 4} = 0.71 m {s}^{-} 1$