# An object vibrates in sipmple harmonic motion with time period 1.6 sec after passing the equilibrium position by 0.2 sec the speed of the object was 1.0m/s, what is the amplitude of the simple harmonic motion of the object? A)0.25m B)0.36m C)3.93m D)18.58

##### 2 Answers

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Option ( B)

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Let the object

Considering that time count is started when the object is at origin. So we can write the equation for displacement

Here origin is also its equilibrium position and It returns repeatedly to this position after each complete oscillation for 1.6s.

So the velocity

Now it is given that the velocity of the object after passing the equilibrium position by

So we can insert

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(a) 0.25 m

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Time period = 1.6 s

Angular frequency,

Since we know the object passes the equilibrium with a velocity of 1.0 m s⁻¹ that is the object's maximum velocity.

Use this equation to solve the problem:

So the answer is (a)

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