# An object with a mass of 10 g is dropped into 120 mL of water at 0^@C. If the object cools by 60 ^@C and the water warms by 5 ^@C, what is the specific heat of the material that the object is made of?

Mar 5, 2016

${c}_{o} = 1 \text{ "(Cal)/(gr*^o C)" made of water}$

#### Explanation:

${Q}_{o} = {m}_{o} \cdot {c}_{o} \cdot \Delta {t}_{o} \text{ Heat given by Object}$
${Q}_{o} = 10 \cdot {c}_{o} \cdot 60 = 600 \cdot {c}_{o}$
${Q}_{w} = {m}_{w} \cdot {c}_{w} \cdot \Delta {t}_{w} \text{ Heat gained by water}$
$120 \text{ " m L" of water:120 gr}$
${c}_{w} = 1 \frac{C a l}{g r {\cdot}^{o} C}$
${Q}_{w} = 120 \cdot 1 \cdot 5 = 600$
${W}_{o} = {Q}_{w}$
$600 \cdot {c}_{o} = 600$
${c}_{o} = 1 \text{ "(Cal)/(gr*^o C)" made of water}$