An object with a mass of #10 g# is dropped into #120 mL# of water at #0^@C#. If the object cools by #60 ^@C# and the water warms by #5 ^@C#, what is the specific heat of the material that the object is made of?

1 Answer
Mar 5, 2016

Answer:

#c_o=1 " "(Cal)/(gr*^o C)" made of water"#

Explanation:

#Q_o=m_o*c_o*Delta t_o" Heat given by Object"#
#Q_o=10*c_o*60=600*c_o#
#Q_w=m_w*c_w*Delta t_w" Heat gained by water"#
#120" " m L" of water:120 gr"#
#c_w=1 (Cal)/(gr*^o C)#
#Q_w=120*1*5=600#
#W_o=Q_w#
#600*c_o=600#
#c_o=1 " "(Cal)/(gr*^o C)" made of water"#