Question

An object with a mass of `10 g` is dropped into `120 mL` of water at `0^@C`. If the object cools by `60 ^@C` and the water warms by `5 ^@C`, what is the specific heat of the material that the object is made of?

Answer 1

`c_o=1 " "(Cal)/(gr*^o C)" made of water"`

Explanation:

`Q_o=m_o*c_o*Delta t_o" Heat given by Object"`
`Q_o=10*c_o*60=600*c_o`
`Q_w=m_w*c_w*Delta t_w" Heat gained by water"`
`120" " m L" of water:120 gr"`
`c_w=1 (Cal)/(gr*^o C)`
`Q_w=120*1*5=600`
`W_o=Q_w`
`600*c_o=600`
`c_o=1 " "(Cal)/(gr*^o C)" made of water"`