# An object with a mass of 100 g is dropped into 500 mL of water at 0^@C. If the object cools by 20 ^@C and the water warms by 4 ^@C, what is the specific heat of the material that the object is made of?

Jul 28, 2017

Specific heat of the object is $1$

#### Explanation:

In such cases, heat lost is equal to heat gained. Further heat lost / gained is given by $m s t$, where $m$ is the mass of the object, $s$ is its specific heat and $t$ is rise / fall in temperature.

Hence let $s$ be the specific heat of the object, then heat lost by the object is $100 \times s \times 20 = 2000 s$ calories

annd heat gained by water is $500 \times 1 \times 4 = 2000$ calories.

Hence $2000 s = 2000$ or $s = 1$