An object with a mass of #12 kg# is on a surface with a kinetic friction coefficient of # 2 #. How much force is necessary to accelerate the object horizontally at # 3 m/s^2#?

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Answer 1 · 2018-08-12T06:45:50

The force is #=271.2N#

The coefficient of kinetic friction is

#mu_k=F_r/N#

The mass of the object is #m=12kg#

The acceleration due to gravity is #g=9.8ms^-2#

The normal reaction is #N=12g#

The coefficient of kinetic friction is #mu_k=2#

Therefore,

#F_r=mu_kN=2*12g=24g#

#F-F_r=ma#

The acceleration is

#a=3ms^-2#

Therefore,

#F=F_r+ma=24g+12*3=24g+36=271.2N#