An object with a mass of # 2 kg# is traveling in a circular path of a radius of #4 m#. If the object's angular velocity changes from # 1 Hz# to # 6 Hz# in # 3 s#, what torque was applied to the object?

1 Answer
Apr 9, 2017

Answer:

88N

Explanation:

first we need to find out the change in instantaneous velocity .
which is from 1 Hz to 6 Hz using formula
#omega#=#(2 piR)/T=vR#
#=>v=2pi/T#
substituting values of 1 Hz as #1/nu=T#
we get the values for instantanious velocity for 2 cases of 1 Hz and
6 Hz as 6.28#ms^(-1)# and #39.26ms^(-1)#
we use the Newton's law of motion according to which
#v=u+a*t#
substituting
u=6.28
v=39.26
and T=3
We get the value for 'a' Acceleration as 10.99#~=#11#ms^(-1)#
For torque =#m*a*R#
we substitute desired values and get 88 N