Question

An object with a mass of `2 kg` is traveling in a circular path of a radius of `4 m`. If the object's angular velocity changes from `1 Hz` to `2 Hz` in `2 s`, what torque was applied to the object?

Answer 1

`L=32pi`

Explanation:

`"the angular acceleration of a rotating object is given by: "`
`alpha=(Delta omega)/(Delta t)`
`alpha=(cancel(2)pi(f_f-f_i))/cancel(2)`
`alpha=pi(2-1)`
`alpha=pi`
`"Torque for an object making rotary motion is given as:"`
`L=alpha*I`
`"we can write " m*r^2 " instead I"`
`L=alpha* m*r^2`
`L=pi*2*4^2`
`L=32pi`