An object with a mass of # 2 kg# is traveling in a circular path of a radius of #4 m#. If the object's angular velocity changes from # 1 Hz# to # 2 Hz# in # 2 s#, what torque was applied to the object?

1 Answer
Feb 13, 2016

Answer:

#L=32pi#

Explanation:

#"the angular acceleration of a rotating object is given by: "#
# alpha=(Delta omega)/(Delta t)#
#alpha=(cancel(2)pi(f_f-f_i))/cancel(2)#
#alpha=pi(2-1)#
#alpha=pi#
#"Torque for an object making rotary motion is given as:"#
#L=alpha*I#
#"we can write " m*r^2 " instead I"#
#L=alpha* m*r^2#
#L=pi*2*4^2#
#L=32pi#