# An object with a mass of 4 g is dropped into 250 mL of water at 0^@C. If the object cools by 120 ^@C and the water warms by 2 ^@C, what is the specific heat of the material that the object is made of?

Feb 16, 2017

The specific heat of the material is =1,042 Kcalkg^-1°C^-1

#### Explanation:

The heat transferred from the hot object, is equal to the heat absorbed by the cold water.

For the cold water,  Delta T_w=2ºC

For the object DeltaT_o=120ºC

${M}_{o} {C}_{o} \left(\Delta {T}_{o}\right) = M w {C}_{w} \left({\Delta}_{w}\right)$

C_w=1Kcalkg^-1ºC^-1

$0 , 004 {C}_{o} 120 = 0 , 250 \cdot 1 \cdot 2$

C_o = 0.5/ 0.48 = 1,042 Kcalkg^-1°C^-1