An object with a mass of 5 kg is on a plane with an incline of pi/8 . If the object is being pushed up the plane with  15 N  of force, what is the net force on the object?

Feb 22, 2018

$- 3.77 \setminus \text{N}$

Explanation:

The net force of this object will take the form of

${F}_{\text{net"=F_"applied"+F_"inclined}}$

Here, the inclined force will be $F = m g \sin \theta$

Since it is opposite to the direction of the push, it will be negative, i.e. $- m g \sin \theta$

So, the equation becomes

${F}_{\text{net"=F_"applied}} - m g \sin \theta$

Plugging in the given values, we get

${F}_{\text{net"=15 \ "N"-5 \ "kg"*9.81 \ "m/s}}^{2} \cdot \sin \left(\frac{\pi}{8}\right)$

${F}_{\text{net"=15 \ "N"-18.77 \ "N}}$

${F}_{\text{net"=-3.77 \ "N}}$

So, the net force will be $3.77 \setminus \text{N}$ to the opposite direction of the push.