An object with a mass of #5 # # kg# is on a surface with a kinetic friction coefficient of # 4 #. How much force is necessary to accelerate the object horizontally at # 6# #ms^-2#?

1 Answer
May 7, 2016

Answer:

#F=F_"frict"+F_"accel"=196+30=226# #N#

Explanation:

The total force required will be given by #F=F_"frict"+F_"accel"# - the sum of the force required to overcome friction and the force required to accelerate the mass.

The frictional force is given by:

#F_"frict"=muF_"norm"# where the normal force #F_"norm"=mg#

So the friction force is #F_"frict"=mumg=4xx5xx9.8=196# #N#

To accelerate a mass the force given by Newton's Second Law is:

#F_"accel"=ma=5xx6=30# #N#

Then:

#F=F_"frict"+F_"accel"=196+30=226# #N#