An object with a mass of #5 kg# is revolving around a point at a distance of #3 m#. If the object is making revolutions at a frequency of #17 Hz#, what is the centripetal force acting on the object?

1 Answer
Jan 18, 2016

Answer:

#1.712xx10^5"N"#

Explanation:

The time period #T# for 1 revolution #=1/f=1/17s#

#v=d/T=(2pir)/T=(2pi3)/(1/17)=320.84"m/s"#

The centripetal force is given by:

#F=(mv^2)/r=(5xx320.84^2)/3=1.712xx10^5"N"#