# An object with a mass of 5 kg is revolving around a point at a distance of 3 m. If the object is making revolutions at a frequency of 1 Hz, what is the centripetal force acting on the object?

Jan 23, 2018

60π^2N

#### Explanation:

$\text{Centripetal force} = \frac{m \cdot {v}^{2}}{r}$
The frequency was given as 1hz
Then "angular velocity" =2πf =(2π" rad")/s
Remember that $\text{linear velocity" = "angular velocity"*"distance}$
$V = r \omega$
Substituting this into the centripetal force formular
$F = \frac{m \cdot r \omega \cdot r \omega}{r}$
$F = m r {w}^{2}$
So using this
F=5 * 3 * 2π * 2π
F=60 * π^2N