An object with a mass of #6 kg# is revolving around a point at a distance of #2 m#. If the object is making revolutions at a frequency of #12 Hz#, what is the centripetal force acting on the object?

1 Answer
Jun 8, 2017

Answer:

The centripetal force is #=68219N#

Explanation:

The cetripetal force is

#F=(mv^2)/r=mromega^2#

The mass is #m=6kg#

The radius is #r=2m#

The frequency is #f=12Hz#

The angular velocity is #omega=2pif=2pi*12=24pirads^-1#

So,

#F=6*2*(24pi)^2=68219N#