# An object with a mass of 6 kg is revolving around a point at a distance of 2 m. If the object is making revolutions at a frequency of 12 Hz, what is the centripetal force acting on the object?

Jun 8, 2017

The centripetal force is $= 68219 N$

#### Explanation:

The cetripetal force is

$F = \frac{m {v}^{2}}{r} = m r {\omega}^{2}$

The mass is $m = 6 k g$

The radius is $r = 2 m$

The frequency is $f = 12 H z$

The angular velocity is $\omega = 2 \pi f = 2 \pi \cdot 12 = 24 \pi r a {\mathrm{ds}}^{-} 1$

So,

$F = 6 \cdot 2 \cdot {\left(24 \pi\right)}^{2} = 68219 N$