An object with a mass of 6 kg is revolving around a point at a distance of 4 m. If the object is making revolutions at a frequency of 1 Hz, what is the centripetal force acting on the object?

Feb 8, 2016

${F}_{c} = 48 \cdot \pi$

Explanation:

$\text{The centripetal force is given by formula :} {F}_{c} = m \cdot {v}^{2} / r$
$\text{we can write: } v = \omega \cdot r$
${F}_{c} = m \cdot {\omega}^{2} \cdot {r}^{2} / r$
${F}_{c} = m \cdot {\omega}^{2} \cdot r$
$\omega = 2 \cdot \pi \cdot f$
${F}_{c} = 6 \cdot 2 \cdot \pi \cdot 1 \cdot 4$
${F}_{c} = 48 \cdot \pi$