An object with a mass of #7 kg# is revolving around a point at a distance of #8 m#. If the object is making revolutions at a frequency of #12 Hz#, what is the centripetal force acting on the object?

1 Answer
May 30, 2016

Answer:

#F_C=32256 pi^2#

Explanation:

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#m=7 " "kg#
#r=8" "m#

#f=12" "Hz#

#v=(2pir)/T" "v/r=(2pi)/T" "(1)#

#omega=(2pi)/T" "(2)#

#"using (1) and (2)"#

#v/r=omega" "v=omega r" "v^2=omega^2 r^2#

#F_C=m*v^2/r" centripetal force"#

#F_C=(m*omega^2*r^2)/r#

#F_C=m*omega^2*r#

#F_C=m*omega^2*r" "omega=2pi f" "omega=2 pi*12" "omega^2=4pi^2*144#

#omega^2=576pi^2#

#F_C=7*576pi^2*8#

#F_C=32256 pi^2#