Question

An object with a mass of `8 kg` is traveling in a circular path of a radius of `12 m`. If the object's angular velocity changes from `15 Hz` to `7 Hz` in `6 s`, what torque was applied to the object?

Answer 1

Torque=-803.52 Newton.meter

Explanation:

`f_1=15 Hz`
`f_2=7 Hz`
`w_1=2*3.14*15 =30*3.14=94.2( rad)/s`
`w_2=2*3.14*7=14*3.13=43.96 (rad)/s`
`a=(w_2-w_1)/t`
`a=(43.96-94.2)/6`
`a=-8.37 m/s^2`
`F=m*a`
`F=-8*8.37=-66.96 N`
`M=F*r`
`M=-66.96*12=-803.52` , Newton.meter