An unknown solid monoprotic acid is titrated with 0.100 M NaOH. It takes 42.34 mL of the base to neutralize 0.525 g of the acid. What is the molar mass of the acid? (Hint: the acid and base react in a 1:1 molar ratio; molar mass had units grams/mol.)

1 Answer
Hriman
May 7, 2018

#124 " g/mol HA"#

Explanation:

Use dimensional analysis:

#(0.525 "g HA")/ (42.34 cancel"ml NaOH")xx (1000 cancel"ml NaOH")/ (1cancel"L NaOH")xx(1cancel"L NaOH")/ (0.1 cancel"mol NaOH")xx (1cancel"mol NaOH")/ (1 "mol HA")= 124 " g/mol HA"#

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