Angela needs 20 quarts of 50% antifreeze solution in her radiator. She plans to obtain this by mixing some pure antifreeze with an appropriate amount of a 40% antifreeze solution. How many quarts of each should she use?

1 Answer
Feb 14, 2018

#3 1/3# quarts of pure antifreeze solution to be mixed with
#16 2/3# quartz of #40%# antifreeze solution.

Explanation:

Say Angela mixes #x# quarts of pure#100%#antifreeze solution

with #(20-x)# quarts of #40%#antifreeze solution to achieve

#50%#antifreeze slution of #20# quart. Balancing we get,

#x* 100/100+(20-x)*40/100=20*50/100 # or

#x+(20-x)0.4= 10 or x-0.4x =10-8 or 0.6 x = 2 # or

#x= 2/0.6=20/6=10/3 = 3 1/3# quartz #:. 20-x =20 -10/3#

#= 50/3 = 16 2/3# quart. Hence #3 1/3# quarts of pure antifreeze

solution to be mixed with #16 2/3#quartz of #40%#antifreeze

solution. {Ans]