Answer? ctg(π-a)cos(π/2-a)-sin(3π/2+a)

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Answer 1 · 2018-04-26T17:11:26

The answer #a=pi/2# or #a=(3pi)/2#

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#cot(π-a)*cos(π/2-a)-sin(3π/2+a)=0#

#cot(pi-a)# lies in the second quadrant #cot(pi-a)=-cot(a)#

#cos(π/2-a)# lies in the first quadrant #cos(π/2-a)=sin(a)#

#sin(3π/2+a)# lies in the fourth quadrant #sin(3π/2+a)=-cos(a)#

The equation formula become #[-cot(a)]*[sin(a)]-[cos(a)]=0#

#cota=cosa/sina#

#[-cosa/sina]*[sina]-cos(a)=0#

#-cosa-cos(a)=0#

#-2cosa=0#

#cosa=0#

#a=pi/2# or #a=(3pi)/2#