# As an acid sulphur dioxide reacts with sodium hydroxide solution to form a salt called sodium sulphate Na2SO3 and water. Write a balanced chemical equation for the reaction (show state symbols)?

Apr 13, 2018

$S {O}_{2} \left(g\right) + 2 N a O {H}_{\left(s\right)} \to N {a}_{2} S {O}_{3} \left(s\right) + {H}_{2} {O}_{\left(l\right)}$

#### Explanation:

$S {O}_{2} + N a O H \to N {a}_{2} S {O}_{3} + {H}_{2} O$

Now, a balanced equation of a reaction has equal atoms of each element on both sides. So we count the atoms each element.

• We have $1$ atom of Sulphur on the one side ($S {O}_{2}$) and $1$ on the other side ($N {a}_{2} S {O}_{3}$).

• We have $3$ atoms of Oxygen on the one side ($S {O}_{2}$ and $N a O H$), but $4$ on the other side ($N {a}_{2} S {O}_{3}$ and ${H}_{2} O$).

• We have $1$ atom of Sodium ($N a O H$), but $2$ on the other side ($N {a}_{2} S {O}_{3}$).

• We have $1$ atom of Hydrogen ($N a O H$), but $2$ on the other side (${H}_{2} O$).

So to balance it:

$S {O}_{2} \left(g\right) + 2 N a O {H}_{\left(s\right)} \to N {a}_{2} S {O}_{3} \left(s\right) + {H}_{2} {O}_{\left(l\right)}$

$S {O}_{2}$ is a gas.
$N a O H$ is a powder, which means its solid.
$N {a}_{2} S {O}_{3}$ is a salt in the form of a powder, which is solid.
${H}_{2} O$ is liquid, for obvious reasons.