As the string passes through the vertical, the narrow beam of light is interrupted by the cylinder for 22 ms . The cylinder has a diameter of 2.5 cm. How to calulate the actual speed of the cylinder?

1 Answer
A08
Jul 6, 2018

Distance moved by the cylinder as it interrupts the beam of light #="Diameter of cylinder"=2.5\ cm#
Time taken to cover this distance #=22\ ms#
Average speed of the cylinder #v_a="Distance"/"Time"#

#=>v_a=(2.5/100)/(22xx10^-3)#
#=>v_a=1.14\ ms^-1#, rounded to two decimal places.

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Assuming that full question is Question 1 part (c)i

(b) #1/2mv^2=mgh#
#=>v=sqrt(2gh)#
#=>v=sqrt(2xx10xx(2-1.932))=1.17\ ms^-1#

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