As the string passes through the vertical, the narrow beam of light is interrupted by the cylinder for 22 ms . The cylinder has a diameter of 2.5 cm. How to calulate the actual speed of the cylinder?

1 Answer
Jul 6, 2018

Distance moved by the cylinder as it interrupts the beam of light ="Diameter of cylinder"=2.5\ cm
Time taken to cover this distance =22\ ms
Average speed of the cylinder v_a="Distance"/"Time"

=>v_a=(2.5/100)/(22xx10^-3)
=>v_a=1.14\ ms^-1, rounded to two decimal places.

.-.-.-.-.-.-.-.-.-.-.-.-.-

Assuming that full question is Question 1 part (c)i

(b) 1/2mv^2=mgh
=>v=sqrt(2gh)
=>v=sqrt(2xx10xx(2-1.932))=1.17\ ms^-1