# Asolution is made by dissolving 14.0g of potassium chloride to a final volume of 78.9mL solution. What is the weight /volume % of the solute?

##### 1 Answer

#### Explanation:

The thing to remember about a solution's *mass by volume percent concentration*,

This implies that you can find a solution's mass by volume percent concentration by determining how many grams of solute you get in

#color(blue)(|bar(ul(color(white)(a/a)"% m/v" = "no. of grams of solute / 100 mL solution"color(white)(a/a)|)))#

Now, you know that your solution is made by dissolving

You can use this information as a **conversion factor** to calculate the number of grams of potassium chloride present in

#100 color(red)(cancel(color(black)("mL solution"))) * overbrace("14.0 g KCl"/(78.9color(red)(cancel(color(black)("mL solution")))))^(color(blue)("given by the problem")) = "17.744 g KCl"#

Since this is how many grams of solute you get in *percent* symbol,

#"% m/v" = color(green)(|bar(ul(color(white)(a/a)color(black)("17.7% KCl")color(white)(a/a)|)))#

The answer is rounded to three **sig figs**.