Assume that y varies inversely as x, how do you write an inverse variation equation that relates x and y given y=-1 when x=-12?

2 Answers
Jan 4, 2018

Answer:

#y=12/x#

Explanation:

We know that #ypropto1/x#, and since #y# is proportional to #1/x# we can add a constant, #y=k1/x#.

To find #k# we rearrange to get #k=yx#

We are given #x# and #y#, so we just put our values in to get #k=xy=-12*-1=12#

#y=12*1/x=12/x#

Jan 4, 2018

Answer:

#y-12/x#

Explanation:

#"the initial statement is "yprop1/x#

#"to convert to an equation multiply by k the constant"#
#"of variation"#

#rArry=kxx1/x=k/x#

#"to find k use the given condition"#

#y=-1" when "x=-12#

#y=k/xrArrk=yx=-12xx-1=12#

#"equation is " color(red)(bar(ul(|color(white)(2/2)color(black)(y=12/x)color(white)(2/2)|)))#