# At constant pressure and 25 °C a sample of gas occupies 4.5 liters. At what temperature will the gas occupy 9.0 liters?

Dec 7, 2014

The answer is $596.3 K$.

This is a simple example of Charles' law

${V}_{1} / {T}_{1} = {V}_{2} / {T}_{2}$,

which states that the volume of a gas is directly proportional to its temperature in K.

We know ${V}_{1}$ = $4.5 L$, ${T}_{1} = \left(25 + 273.15\right) = 298.15 K$, and ${V}_{2}$ = $9 L$, therefore

${T}_{2} = {V}_{2} / {V}_{1} \cdot {T}_{1} = \frac{9}{4.5} \cdot 298.15 = 596.4 K$ -> double the volume translates to double the temperature, and vice versa.