At what temperature will 14.0 g of #H_2# occupy a volume of 15.5L at a pressure of 204 kPa?

1 Answer
Jan 19, 2017

Answer:

#T=(PV)/(nR)~=50*K#

Explanation:

Of course, we need to find the appropriate gas constant.

This site gives me #R= 8.314*L*kPa* K^-1* mol^-1#.

Given this, we plug in the numbers:

#T=(204*kPaxx15.5*L)/((14.0*g)/(2.016*g*mol^-1)xx8.314*L*kPa* K^-1* mol^-1)#

We should get an answer in #1/K^-1=1/(1/K)=K# as required for an #"absolute temperature"#.

The temperature is so low because there is a large molar quantity of dihydrogen. At this temperature we would anticipate some deviation from ideality. We are in no position to assess this.