Question

At what temperature wwill o.654 moles of neon gas occupy 12.30l at 1.95 atm?

Answer 1

`"446.7 K"`

Explanation:

Use ideal gas equation

`"PV = nRT"`

`"T" = "PV"/"nR" = "1.95 atm × 12.30 L"/"0.654 mol × 0.0821 L atm / (mol K)" = "446.7 K"`