# B) A force of 90 N is used to pull a truck 200 m along a horizontal floor. Determine the work done and the increase in K. E if there is no energy loss due to friction. ?

$18 \setminus k J$ & $18 \setminus k J$

#### Explanation:

Work done to pull a truck by applying a force of $90 N$ through a distance $200 \setminus m$ in the same direction

$= \setminus \textrm{f \mathmr{and} c e} \setminus \times \setminus \textrm{\mathrm{di} s p l a c e m e n t \in t h e \mathrm{di} r e c t i o n o f f \mathmr{and} c e}$

$= 90 \setminus \times 200$

$= 18000 \setminus N m$

$= 18 \setminus k J$

Since, there is no loss of energy due to friction hence the total work done on the truck will be converted into Kinetic energy (K.E.) of truck. Hence change in K.E.

$= \setminus \textrm{w \mathmr{and} k \mathrm{do} \ne} = 18 \setminus k J$