Balance the following reaction: #"__Fe +___NaBr"##rarr##"____FeBr"_3 + "___Na"#?

and what reaction would this be classified as?
-Synthesis
-Single Replacement
-Decomposition
-Combustion
-Double replacement

1 Answer
Jan 16, 2018

#"Fe + 3NaBr"##rarr##"FeBr"_3 + "3Na"#

#"Fe + 3NaBr"##rarr##"no reaction"# (Refer to the explanation.)

Single replacement (displacement) reaction format.

Explanation:

Balanced equation

#"Fe + 3NaBr"##rarr##"FeBr"_3 + "3Na"#

This is in the form of a single replacement (displacement) reaction. However, the elemental metal replacing the metal in the compound must be more reactive than the metal in the compound.

If you consult a metal reactivity series, you will see that iron (Fe) cannot replace sodium (Na) because it is less reactive than sodium. So this reaction would not take place.

#"Fe + 3NaBr"##rarr##"no reaction"#

The opposite reaction would occur.

#"3Na + FeBr"_3"##rarr##"Fe + 3NaBr"#

A metal can only replace (displace) a metal below it in the series. Note that Na is above Fe in the series.

http://www.frankswebspace.org.uk/ScienceAndMaths/chemistry/reactivitySeries.htm