Beginning trig... find csc?

Question

In right triangle ABC, where angle C is the right angle, $sec B = \frac{\sqrt{117}}{9}$ $secB=sqrt117/9$ Find csc A.

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Answer 1 · 2018-01-23T17:45:23

$csc A = sec B = \frac{\sqrt{117}}{9}$ $cscA=secB=sqrt117/9$

$csc A = \frac{1}{sin A} = \frac{1}{sin (90 - B)} = \frac{1}{cos B} = sec B = \frac{\sqrt{117}}{9}$ $cscA=1/sinA=1/sin(90-B)=1/cosB=secB=sqrt117/9$