# Bobs age is 4 times greater than Susanne's age. Dakota is three years younger than susanne. The sum of Bob's, Susanne's, and Dakota's ages is 93. What is than Susanne's age?

##### 1 Answer
Nov 11, 2016

Susanne's age is 16

#### Explanation:

First let's call Susanne's age $S$.

Because Bob is 4 times greater than Susanne's age his age must be $4 \times S$

And because Dakota is three years younger than Susanne her age must be $S - 3$

The sum of all their ages is 93, so adding together the terms we have created gives us:

$S + 4 S + \left(S - 3\right) = 93$

Now solving for $S$ while keeping this equation balanced gives:

$S + 4 S + S - 3 = 93$

$6 S - 3 = 93$

$6 S - 3 + 3 = 93 + 3$

$6 S = 96$

$\frac{6 S}{6} = \frac{96}{6}$

$S = 16$