Bobs age is 4 times greater than Susanne's age. Dakota is three years younger than susanne. The sum of Bob's, Susanne's, and Dakota's ages is 93. What is than Susanne's age?

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Answer 1 · 2016-11-11T14:46:21

Susanne's age is 16

First let's call Susanne's age #S#.

Because Bob is 4 times greater than Susanne's age his age must be #4 xx S#

And because Dakota is three years younger than Susanne her age must be #S - 3#

The sum of all their ages is 93, so adding together the terms we have created gives us:

#S + 4S + (S - 3) = 93#

Now solving for #S# while keeping this equation balanced gives:

#S + 4S + S - 3 = 93#

#6S - 3= 93#

#6S - 3 + 3 = 93 + 3#

#6S = 96#

#(6S)/6 = 96/6#

#S = 16#