# Brent had $26 when he went to the fair. After playing 5 games and then 2 more, he had$15.50 left. How do you solve 15.50=26-5p-2p to find the price for each game?

Jun 23, 2017

$1.50 #### Explanation: 1. Combine like terms. $- 5 p$and $- 2 p$can be combined to make $- 7 p$, so now the equation is $15.50 = 26 - 7 p$This makes sense because he played 5 games, then 2 more, so that's 7 games in total. 2. Subtract 26 from both sides to isolate the variable $p$. $15.50 \textcolor{b l u e}{- 26} = 26 - 7 p \textcolor{b l u e}{- 26}$$- 10.5 = - 7 p$3. Divide both sides by $- 7$to find the value of $p$. $\frac{- 10.5}{-} 7 = \frac{- 7 p}{-} 7$$1.5 = p$The price of each game is$1.50.

Hope this helps!

Jun 23, 2017

$p = 1.50$

#### Explanation:

First, combine like terms. We have $- 5 p$ and $- 2 p$. Combine their coefficients:

$- 5 p - 2 p = \left(- 5 - 2\right) p = - 7 p$

So now we have:

$15.50 = 26 - 7 p$

Subtract $26$ on both sides to isolate the $p$s:

$15.50 - 26 = 26 - 7 p - 26$

This becomes:

$- 10.50 = - 7 p$

Now divide both sides by $- 7$:

$- \frac{10.50}{-} 7 = - 7 \frac{p}{-} 7$

This becomes:

$1.5 = p$

So each game costs $1.50$