We begin by balancing the
Now, counting the number of
Is there a question here? Of course you want to represent the BALANCED combustion equation.
The usual rigmarole in these combustion equations is to balance the carbons as carbon dioxide...then balance the hydrogens as water, and THEN balance the oxygens by adding in dioxygen.. And so ...
And thus finally, garbage out equals garbage in, and the equation is stoichiometrically balanced with respect to mass and charge. You can double the equation if you like in order to remove the half-integral oxygen coefficient. I have never seen the need to do so, especially as the arithmetic is easier in this form.
How many grams of dioxygen gas are needed for combustion of