Calcium hydride combines with water according to the equation: #CaH_2(s) + 2H_2O(ℓ) -> 2H_2(g) + Ca(OH)_2(s)#? Beginning with with 84.0 g of #CaH_2(s)# and 36.0 g of #H_2O#, what volume of #H_2# will be produced at 273 K and a pressure of 1520 torr?
Calculate the number of moles of each of the reactants to determine what the limiting reagent is
You have two moles of each, but in order to fully react you would need four moles of
There is a
Now you can use the ideal gas equation, inserting all the values we know so far
We know that
Since the question is asking the volume, we can rearrange the ideal gas equation and plug in these values to get