Question

Calculate the amount of heat required to raise the temperature of an 83 g sample of water from 36 c to 69 c ?

Answer 1

`"11 000 J"` of heat energy is required.

Explanation:

Use the following formula:

`q=mcDeltaT`,

where:

`q` is heat energy, `m` is mass, `c` is specific heat, and `DeltaT` is change in temperature. `DeltaT=T_"final"-T_"initial"`

Organize the data:

Known/Given

`m="83 g"`

`c=("4.184 J")/("g"*""^@"C")`

`T_"initial"=36^@"C"`

`T_"final"=69^@"C"`

`DeltaT="69"^@"C"-"36"^@"C"="33"^@"C"`

Unknown

`q`

Solution

Plug in the known/given values and solve.

`q=(83color(red)cancel(color(black)("g")))xx(("4.184 J")/(color(red)cancel(color(black)("g"))*""^@color(red)cancel(color(black)("C"))))xx(33^@color(red)cancel(color(black)("C")))="11 000 J"` (rounded to two significant figures)